2x^2+(2-i)x+1=0

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Solution for 2x^2+(2-i)x+1=0 equation:


Simplifying
2x2 + (2 + -1i) * x + 1 = 0

Reorder the terms for easier multiplication:
2x2 + x(2 + -1i) + 1 = 0
2x2 + (2 * x + -1i * x) + 1 = 0

Reorder the terms:
2x2 + (-1ix + 2x) + 1 = 0
2x2 + (-1ix + 2x) + 1 = 0

Reorder the terms:
1 + -1ix + 2x + 2x2 = 0

Solving
1 + -1ix + 2x + 2x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1ix + 2x + -1 + 2x2 = 0 + -1

Reorder the terms:
1 + -1 + -1ix + 2x + 2x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1ix + 2x + 2x2 = 0 + -1
-1ix + 2x + 2x2 = 0 + -1

Combine like terms: 0 + -1 = -1
-1ix + 2x + 2x2 = -1

Add '-2x' to each side of the equation.
-1ix + 2x + -2x + 2x2 = -1 + -2x

Combine like terms: 2x + -2x = 0
-1ix + 0 + 2x2 = -1 + -2x
-1ix + 2x2 = -1 + -2x

Add '-2x2' to each side of the equation.
-1ix + 2x2 + -2x2 = -1 + -2x + -2x2

Combine like terms: 2x2 + -2x2 = 0
-1ix + 0 = -1 + -2x + -2x2
-1ix = -1 + -2x + -2x2

Divide each side by '-1x'.
i = x-1 + 2 + 2x

Simplifying
i = x-1 + 2 + 2x

Reorder the terms:
i = 2 + x-1 + 2x

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